diff options
author | Yigit Sever | 2020-12-02 00:29:04 +0300 |
---|---|---|
committer | Yigit Sever | 2020-12-02 00:29:04 +0300 |
commit | 18539f03d200fb94d59f102207213c3c80cdc5d7 (patch) | |
tree | bbba81b4f4fb1bb747833ee6b913c64c28065e6d /answer_sheet | |
parent | a10bc230a9644e0a951b62c1450f25aec698a063 (diff) | |
download | hw3-main.tar.gz hw3-main.tar.bz2 hw3-main.zip |
both a and b
Diffstat (limited to 'answer_sheet')
-rw-r--r-- | answer_sheet/main.pdf | bin | 169720 -> 194172 bytes | |||
-rw-r--r-- | answer_sheet/main.tex | 32 | ||||
-rw-r--r-- | answer_sheet/quiver.sty | 36 | ||||
-rw-r--r-- | answer_sheet/structure.tex | 1 |
4 files changed, 69 insertions, 0 deletions
diff --git a/answer_sheet/main.pdf b/answer_sheet/main.pdf index 7e9b4c4..5d1a4d4 100644 --- a/answer_sheet/main.pdf +++ b/answer_sheet/main.pdf | |||
Binary files differ | |||
diff --git a/answer_sheet/main.tex b/answer_sheet/main.tex index 002a755..67e2b09 100644 --- a/answer_sheet/main.tex +++ b/answer_sheet/main.tex | |||
@@ -98,5 +98,37 @@ Our algorithm is then as follows; | |||
98 | 98 | ||
99 | The cycle checking step, step 2 in the algorithm above uses the Union Find. Since we did not go into the detail of Union Find in the lectures we will use the naive approach which uses $\mathcal{O}(n^{2})$ operations. On top of that, we have to run Kruskal's algorithm twice for $T_{r}$ and $T_{w}$ which runs in order $\mathcal{O}(k\log(n))$ ($k$ can be substituted with the number of white edges, if higher). Overall, the runtime of the algorithm is $\mathcal{O}(n^{2} k\log(n))$. | 99 | The cycle checking step, step 2 in the algorithm above uses the Union Find. Since we did not go into the detail of Union Find in the lectures we will use the naive approach which uses $\mathcal{O}(n^{2})$ operations. On top of that, we have to run Kruskal's algorithm twice for $T_{r}$ and $T_{w}$ which runs in order $\mathcal{O}(k\log(n))$ ($k$ can be substituted with the number of white edges, if higher). Overall, the runtime of the algorithm is $\mathcal{O}(n^{2} k\log(n))$. |
100 | 100 | ||
101 | \section{Shortest-paths and min spanning trees}% | ||
102 | \label{sec:shortest_paths_and_min_spanning_trees} | ||
103 | |||
104 | \subsection{a}% | ||
105 | \label{sub:a} | ||
106 | |||
107 | We will assume the tree of shortest paths is a spanning tree (otherwise node $s$ on its own is a tree and the answer is trivial). | ||
108 | |||
109 | For a graph $G = (V, E)$, we can have $T = (V, E')$ which is a tree of shortest paths and a minimum spanning tree $T' = (V, E'')$. Take any edge incident to $s$ and call it $k$. $k = (s, x)$ is the minimum weighted edge from $s$ to $x$ per definition of the tree of shortest paths. Suppose that the MST $T'$ does not include $k$. This implies that there exists a path in $T'$ $s \leadsto x$ that does not include $k$. Adding $k$ to the MST will introduce a cycle but we can break this cycle by using the Cycle property given in the Greedy Algorithms II lecture notes. Since $k = (s, x)$ is the minimum weighted edge, it will not get deleted which means MST should have included $k$ to begin with. | ||
110 | |||
111 | So it is not possible for a tree of shortest paths and a MST to not share any edges. | ||
112 | |||
113 | \[\begin{tikzcd} | ||
114 | {x} \\ | ||
115 | {s} \\ | ||
116 | & {S} | ||
117 | \arrow[from=2-1, to=3-2, dashed, no head] | ||
118 | \arrow[from=3-2, to=1-1, curve={height=24pt}, no head] | ||
119 | \arrow["{k}"', from=1-1, to=2-1, no head] | ||
120 | \end{tikzcd}\] | ||
121 | |||
122 | |||
123 | \subsection{b}% | ||
124 | \label{sub:b} | ||
125 | |||
126 | Given the acyclic digraph $G = (V, E)$ and an arborescence $A \subset E$ with the given conditions in the question text, $A$ itself is then a minimum cost arborescence in $G$. Take any $e = (v, t) \in A$. If $e$ is part of some minimum cost arborescence in $G$ then it is the cheapest incoming edge for $t$ per the lecture notes. $A$ is built up from such $e$ and the algorithm for building an arborescence in $G$ per the lecture notes is picking the cheapest incoming edge for every node and the graph $G$ is acyclic meaning that we cannot form accidental cycles by including every $e \in E$, $A$ is a minimum-cost arborescence in $G$. | ||
127 | |||
128 | |||
129 | |||
130 | |||
131 | |||
132 | |||
101 | 133 | ||
102 | \end{document} | 134 | \end{document} |
diff --git a/answer_sheet/quiver.sty b/answer_sheet/quiver.sty new file mode 100644 index 0000000..57d154b --- /dev/null +++ b/answer_sheet/quiver.sty | |||
@@ -0,0 +1,36 @@ | |||
1 | % *** quiver *** | ||
2 | % A package for drawing commutative diagrams exported from https://q.uiver.app. | ||
3 | % | ||
4 | % This package is currently a wrapper around the `tikz-cd` package, importing necessary TikZ | ||
5 | % libraries, and defining a new TikZ style for curves of a fixed height. | ||
6 | % | ||
7 | % Version: 1.0.1 | ||
8 | % Authors: | ||
9 | % - varkor (https://github.com/varkor) | ||
10 | % - AndréC (https://tex.stackexchange.com/users/138900/andr%C3%A9c) | ||
11 | |||
12 | \NeedsTeXFormat{LaTeX2e} | ||
13 | \ProvidesPackage{quiver}[2020/11/27 quiver] | ||
14 | |||
15 | % `tikz-cd` is necessary to draw commutative diagrams. | ||
16 | \RequirePackage{tikz-cd} | ||
17 | % `calc` is necessary to draw curved arrows. | ||
18 | \usetikzlibrary{calc} | ||
19 | % `pathmorphing` is necessary to draw squiggly arrows. | ||
20 | \usetikzlibrary{decorations.pathmorphing} | ||
21 | |||
22 | % A TikZ style for curved arrows of a fixed height, due to AndréC. | ||
23 | \tikzset{curve/.style={settings={#1},to path={(\tikztostart) | ||
24 | .. controls ($(\tikztostart)!\pv{pos}!(\tikztotarget)!\pv{height}!270:(\tikztotarget)$) | ||
25 | and ($(\tikztostart)!1-\pv{pos}!(\tikztotarget)!\pv{height}!270:(\tikztotarget)$) | ||
26 | .. (\tikztotarget)\tikztonodes}}, | ||
27 | settings/.code={\tikzset{quiver/.cd,#1} | ||
28 | \def\pv##1{\pgfkeysvalueof{/tikz/quiver/##1}}}, | ||
29 | quiver/.cd,pos/.initial=0.35,height/.initial=0} | ||
30 | |||
31 | % TikZ arrowhead/tail styles. | ||
32 | \tikzset{tail reversed/.code={\pgfsetarrowsstart{tikzcd to}}} | ||
33 | \tikzset{2tail/.code={\pgfsetarrowsstart{Implies[reversed]}}} | ||
34 | \tikzset{2tail reversed/.code={\pgfsetarrowsstart{Implies}}} | ||
35 | |||
36 | \endinput | ||
diff --git a/answer_sheet/structure.tex b/answer_sheet/structure.tex index 77d3e4c..5a9fcbe 100644 --- a/answer_sheet/structure.tex +++ b/answer_sheet/structure.tex | |||
@@ -34,6 +34,7 @@ | |||
34 | \usepackage{caption} | 34 | \usepackage{caption} |
35 | \usepackage{tikz} | 35 | \usepackage{tikz} |
36 | \usepackage{subcaption} | 36 | \usepackage{subcaption} |
37 | \usepackage{quiver} | ||
37 | \usetikzlibrary{arrows,fit,positioning} | 38 | \usetikzlibrary{arrows,fit,positioning} |
38 | \usepackage[style=authoryear]{biblatex} | 39 | \usepackage[style=authoryear]{biblatex} |
39 | 40 | ||