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@@ -85,13 +85,79 @@ With the assumption that accessing the labels $(u, w)$ takes $\mathcal{O}(1)$ ti
85\section{Reachability}% 85\section{Reachability}%
86\label{sec:reachability} 86\label{sec:reachability}
87 87
88First, compute all strongly connected components (SCCs) of $G$ by using~\parencite{tarjanDepthFirst1972} per \emph{page 72} of the \nth{3} lecture notes in $\mathcal{O}(E+V)$ time. Instead of labelling the SCCs with the root node, we will initially label all nodes of the SCC $F'$ with the $min(u)$ of the connected component. 88The intuition for this question can be illustrated as follows;
89 89
90Then, by ignoring the tree edges, shrink the graph $G$ such that $E' = {(v, w)~|~v \in F', w \in F''}$, leaving only cross links behind. This step takes another $\mathcal{O}(E+V)$ time. 90If $G$ is strongly connected then the answer is trivial; every vertex have the same $\min(u) = 1$.
91 91
92Now run the topological sort algorithm presented in \emph{page 84} of the \nth{3} lecture notes this operation is yet again $\mathcal{O}(E+V)$. 92For a directed acyclic graph, consider the scenario below;
93 93
94Finally, reverse the direction of the edges on the graph that have been output by the topological sort and starting from the new root node, traverse the graph downwards and update the $min(u)$ of every SCC as follows; 94\begin{tikzpicture}
95 [vertex/.style={circle,draw,thick,minimum size=6mm,inner sep=10pt},
96 edge/.style={->,>=stealth',line width=1pt]}]
97
98 \node[vertex] (0) {$a$};
99 \node[vertex] (1) [right=of 0] {$b$};
100 \node[vertex] (2) [right=of 1] {$c$};
101 \node[vertex] (3) [right=of 2] {$d$};
102
103 \node [above,xshift=-5mm] at (0.north west) {$L(u) = 4$};
104 \node [above] at (1.north) {$L(u) = 1$};
105 \node [above] at (2.north) {$L(u) = 3$};
106 \node [above,xshift=5mm] at (3.north east) {$L(u) = 2$};
107
108 % \node [red,below] at (0.south) {$\min(u) = 1$};
109 % \node [red,below] at (1.south) {$\min(u) = 1$};
110 % \node [red,below] at (2.south) {$\min(u) = 2$};
111 % \node [red,below] at (3.south) {$\min(u) = 3$};
112
113 \draw [edge] (0) to (1);
114 \draw [edge,bend left=45] (0) to (3);
115 \draw [edge] (1) to (2);
116 \draw [edge] (2) to (3);
117\end{tikzpicture}
118
119We can assign the $\min(u)$ values on this directed acyclic graph by reversing the direction of the edges and traversing the graph, keeping a minimum $\min(u)$ encountered so far for the nodes;
120
121\begin{tikzpicture}
122 [vertex/.style={circle,draw,thick,minimum size=6mm,inner sep=10pt},
123 edge/.style={<-,>=stealth',line width=1pt]}]
124
125 \node[vertex] (0) {$a$};
126 \node[vertex] (1) [right=of 0] {$b$};
127 \node[vertex] (2) [right=of 1] {$c$};
128 \node[vertex] (3) [right=of 2] {$d$};
129
130 \node [above,xshift=-5mm] at (0.north west) {$L(u) = 4$};
131 \node [above] at (1.north) {$L(u) = 1$};
132 \node [above] at (2.north) {$L(u) = 3$};
133 \node [above,xshift=5mm] at (3.north east) {$L(u) = 2$};
134
135 \node [red,below] at (0.south) {$\min(u) = 1$};
136 \node [red,below] at (1.south) {$\min(u) = 1$};
137 \node [red,below] at (2.south) {$\min(u) = 2$};
138 \node [red,below] at (3.south) {$\min(u) = 2$};
139
140 \draw [edge] (0) to (1);
141 \draw [edge,bend left=45] (0) to (3);
142 \draw [edge] (1) to (2);
143 \draw [edge] (2) to (3);
144\end{tikzpicture}
145
146Starting from the \enquote{root} \texttt{d}, the $\min(u)$ is $2$, which is assigned to the immediate neighbours of \texttt{d}, \texttt{c} and \texttt{a}.
147When the traversal \emph{reaches} \texttt{b}, \texttt{b} sets the current $\min(u)$ to $1$ and \texttt{a}'s $\min(u)$ value is updated to $1$ as well.
148
149With the intuition out of the way, we will generalize the problem.
150First, compute all strongly connected components (SCCs) of $G$ by using~\parencite{tarjanDepthFirst1972} per \emph{page 72} of the \nth{3} lecture notes in $\mathcal{O}(E+V)$ time.
151Instead of labelling the SCCs with their root node, we will initially label all nodes of the SCC $F'$ with the $\min(u)$ of the connected component; $\min(a) ~ \text{of} ~ a \in F' = \min{\{L(w) : w \in F'\}}$.
152
153Then, by ignoring the tree edges, \emph{shrink} the graph $G$ such that $E' = \{(v, w)~|~v \in F', w \in F''\}$, leaving only cross links behind.
154This step takes another $\mathcal{O}(E+V)$ time.
155
156Now run the topological sort algorithm presented in \emph{page 84} of the \nth{3} lecture notes.
157This operation is yet again $\mathcal{O}(E+V)$.
158
159We now have a scenario like the one illustrated above.
160Reverse the direction of the edges on the graph that have been output by the topological sort and starting from the new root node, traverse the graph downwards and update the $\min(u)$ of every SCC in $\mathcal{O}(m+n)$ time as follows;
95 161
96{\centering 162{\centering
97 \begin{minipage}{.7\linewidth} 163 \begin{minipage}{.7\linewidth}
@@ -100,13 +166,13 @@ Finally, reverse the direction of the edges on the graph that have been output b
100 \SetAlgoLongEnd{} 166 \SetAlgoLongEnd{}
101 \KwData{$G'$ = topological sorted G with reversed edges} 167 \KwData{$G'$ = topological sorted G with reversed edges}
102 \KwResult{$\min(u)$ for all vertices $u \in V$} 168 \KwResult{$\min(u)$ for all vertices $u \in V$}
103 $\text{mostmin} \longleftarrow \min(\text{root})$\; 169 $\text{minnest} \longleftarrow \min(\text{root})$\;
104 \While{traversing $G'$ downwards with current node $v$}{ 170 \While(\tcp*[f]{$m+n$}){traversing $G'$ downwards with current node $v$}{
105 \uIf{$\min(v) < mostmin$}{ 171 \uIf{$\min(v) < minnest$}{
106 $\text{mostmin} \longleftarrow \min(v)$\; 172 $\text{minnest} \longleftarrow \min(v)$\;
107 } 173 }
108 \Else{ 174 \Else{
109 label $v$ as $mostmin$ 175 label $v$ as $minnest$
110 } 176 }
111 } 177 }
112 \caption{Updating $\min(u)$ of the SCCs}% 178 \caption{Updating $\min(u)$ of the SCCs}%
@@ -116,6 +182,8 @@ Finally, reverse the direction of the edges on the graph that have been output b
116 \par 182 \par
117} 183}
118 184
185Finally, update the $\min(u)$ of every node $w \in G$ to match the cross link edges of the SCC they belong to. This operation is yet another $\mathcal{O}(m+n)$ traversal.
186
119\printbibliography 187\printbibliography
120 188
121\end{document} 189\end{document}